Difference between revisions of "Error Messages/40620"

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= Remedies  =
 
= Remedies  =
  
If L has been defined as a list of objects/handles (Eg. [I, J, K, 'value']), this issue can be fixed by following one of the steps below:<br>
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If L has been defined as a list of objects/handles (Eg. [I, J, K, 'value']), this issue can be fixed by following one of the steps below:<br>  
  
 
#The parameter to MdArrayToTable can be changed from L to IndexValue(L). This will pass on the index value instead of the value to the function.  
 
#The parameter to MdArrayToTable can be changed from L to IndexValue(L). This will pass on the index value instead of the value to the function.  
#Change L to a list of identifier.
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#Change L to a list of identifier, which will convert the I, J and K to identifiers.
  
 
If L is an index, you can also set the Metaonly attribute of the index to 1 to fix this issue.<br>  
 
If L is an index, you can also set the Metaonly attribute of the index to 1 to fix this issue.<br>  
  
 
<br> <comments />
 
<br> <comments />

Revision as of 01:36, 21 January 2010

Error Message Examples

The third parameter, L, passed to MdArrayToTable, is not a 1-D array of identifiers.

You may encounter a subtlety here.  The expression provided for L is evaluated, so the value, rather than the index value, is used.
If you have defined an index L as a list of identifiers, such as [I,J,K,"value"], you must use IndexValue(L) as the third parameter
in order to use L's index value, rather than its evaluted value.  Alternatively, if L is an index, you can set its metaOnly
attribute to 1.

Cause

The third parameter, L, passed to MdArrayToTable is a list of objects/handles, instead of being a list of identifiers.

Example. L is defined as [Index1, Index2, Index3, 'value'] instead of ['Index1', 'Index2', 'Index3', 'value'].

Remedies

If L has been defined as a list of objects/handles (Eg. [I, J, K, 'value']), this issue can be fixed by following one of the steps below:

  1. The parameter to MdArrayToTable can be changed from L to IndexValue(L). This will pass on the index value instead of the value to the function.
  2. Change L to a list of identifier, which will convert the I, J and K to identifiers.

If L is an index, you can also set the Metaonly attribute of the index to 1 to fix this issue.



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